每一个密码子或者编码一种氨基酸，或者告诉这些细胞停止生产这个蛋白质链。

Each codon either codes for an amino acid or tells the cell to stop making a protein chain.

一个服务通常调用其他服务来确定对消费者请求的响应，从而形成一个调用链。

Often one service calls another service in a chain to determine the response to a request from a consumer.

但是这也带来一个问题——如果更老一代中的对象引用一个不能通过从根开始的所有其他引用链到达的更年轻的对象该怎么办？

But this creates a problem — what if an object in the older generation references a younger object, which is not reachable through any other chain of references from a root?

So in this case, one of the standard ways to do this, is to use what's called a linked list.

标准的处理方法是使用链表,我接下来也准备这么做。

And we're having a difference of opinion as to whether we should use a tuple or a list here, right?

可以“是结果,明白了吗？我们队在这里是应该用数组,还是链表还有一些不同意见对吧？

That can happen but that's abnormal, but changes in maybe the chemistry of the backbone that holds the nucleotides together.

这可能发生的,但属于非正常的变化,而是改变诸如维持核苷酸序列的,主链的化学结构